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4.9x^2+5.99x-104=0
a = 4.9; b = 5.99; c = -104;
Δ = b2-4ac
Δ = 5.992-4·4.9·(-104)
Δ = 2074.2801
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5.99)-\sqrt{2074.2801}}{2*4.9}=\frac{-5.99-\sqrt{2074.2801}}{9.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5.99)+\sqrt{2074.2801}}{2*4.9}=\frac{-5.99+\sqrt{2074.2801}}{9.8} $
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